Solucionario Diseño Shigley Cap 5
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30 páginas
budynas_SM_ch05.qxd11/29/2006
15:00
FIRST PAGES
Page 115
Chapter 5
5-1
MSS:
σ1 − σ3 = S y / n
DE:
n=
⇒
Sy σ 2
2
σ = σ A − σ AσB + σB
(a) MSS:
DE:
Sy σ1 − σ3
n=
1/2
2
2
2
= σx − σx σ y + σ y + 3τx y
1/2
σ1 = 12, σ2 = 6, σ3 = 0 kpsi
50
n=
= 4.17 Ans.
12
σ = (122 − 6(12) + 62 ) 1/2 = 10.39 kpsi,
12
±
(b) σ A , σ B =
2
12
2
n=
50
= 4.81
10.39
Ans.
2
+ ( −8) 2 = 16, − 4 kpsi
σ1 = 16, σ2 = 0, σ3 = −4 kpsi
MSS:
DE:
(c) σ A , σ B =
n=
50
= 2.5
16 − ( −4)
Ans.
σ = (122 + 3( −82 )) 1/2 = 18.33 kpsi,
−6 − 10
±
2
−6 + 10
2
n=
50
= 2.73
18.33
Ans.
2
+ ( −5) 2 = −2.615, −13.385 kpsi
σ1 = 0, σ2 = −2.615, σ3 = …ver más…
(5-30a)
n=
BCM: Eq. (5-31a )
Sut
30
=
= 1.5 Ans. σx 20
n=
30
= 1.5 Ans.
20
30 n= = 1.5 Ans.
20
MM: Eq. (5-32a )
(b) σx = 12 kpsi, τx y = −8 kpsi σ A, σB =
12
2
12
±
2
2
+ ( −8) 2 = 16, −4 kpsi
30
= 1.88 Ans.
16
16 ( −4)
1
=
−
⇒ n 30
100
30
= 1.88 Ans. n= 16 n= MNS: Eq. (5-30a)
BCM: Eq. (5-31b)
MM: Eq. (5-32a)
n = 1.74 Ans.
(c) σx = −6 kpsi, σ y = −10 kpsi, τx y = −5 kpsi σ A, σB =
−6