Mecanica De Suelos
GAS
LIQUIDO
SOLIDO
Datos:
Vm = 200cmᶟ
Wm = 260 g
Ss = 2.6
Ss = Ws ÷ (Vs)(ɣo) Vs = 260g ÷ 2.6 g/cmᶟ = 100cmᶟ ɣo = 1 gr/cmᶟ
Vv = Vm – Vs Vv = 200cmᶟ - 100cmᶟ = 100cmᶟ ȼ = Vv ÷ Vs ȼ = 100cmᶟ ÷ 100cmᶟ = 1
2.- el contenido de agua de un suelo saturado es de 40% el Ss de sus partículas es 2.65. Calcule para tal suelo ȼ y ɣm.
LIQUIDO
SOLIDO
Datos:
W% = 40%
Ss = 2.65
Ws = 1
Vs = 1 ÷ 2.65 Vs = 0.3773 ȼ = Vv ÷ Vs ȼ = 0.4 ÷ 0.3773 …ver más…
Calcule Gw, n, w y Yd.
Vs = 1 e= Vv/Vs, eVs= Vv, entonces: Vv= 1x1m^3 = 1 m^3
Ss= Ws/ Vs (&o) entonces: Ws= (Vs)(Ss)(&o) = 1m^3(2.60ton/m^3) = 2.6 ton
&m= Wm/Vm entonces: Wm= &m (Vm) = 1.6 x 2 = 3.2 ton.
&d= Ws/Vm = 2.6 / 2 m^3 = 1.3 ton/ m^3
Gm= Vw/Vv = 0.6m^3 / 1 m^3 = 0.6 x 100% = 60%
n= Vv / Vm = 1 m^3 / 2 m^3 = 0.5 x 100% = 60%
w= 0.6 ton / 2.6 ton = 0.23 x 100% = 23%
8.- En un suelo parcialmente saturado: e = 1.0; w = 32% y Ss = 2.70
Calcule Ym, Gw, Ss, Yd, y n.
e= 1.0 = Vv / Vs entonces si: Vs = 1m^3 Vv = 1m^3
Ws = (Vs) (Ss) (&s) = 1m^3 (2.70 ton/m^3) = 2.7 ton
Gw = Vw/Vv = 0.864 m^3 / 1 m^3 = 0.864 x 100% = 86.4 %
Sm = Wm / Vm (&o) = 3.564 ton / 2 ton = 1.78
&d = Ws / Vm = 2.7 ton / 2 ton = 1.78
&’m = &m - &o = 1.78 ton / m^3 – 1ton/m^3 = 0.78 ton/m^3
n= Vr / Vv = 1 m^3 / 2 m^3
9.- En un suelo saturado: Wm = 200 g; Vs = 60 g; y Ss = 2.70. Calcule: w, e y Ym.
Ss= Ws / Vv (&o) entonces: Ws = (Vs)(Ss)(&o) = 60 cm ^3 ( 2.7 gm/cm^3)
W= 38 /162 = 0.234 x 100% = 23. %
e= Vv / Vs = 38 / 60 =