Bloque I:
Aplicaciones de la cantidad de sustancia en la cuantificación de procesos químicos.

Masa Molar

H2O2= 2+32=34 gr/mol

CO2= 12+32=44 gr/mol

Volumen Molar

100gr C4H10
C4H10= 48+10=58 gr/mol
#mol=100/58= 1.72 mol
Volumen= (1.72 mol) (22.4 mol/L)= 38.52 L

Composición Porcentual

C6H14 = 72+14=86 gr/mol
%C= 72/86(100)= 83.72%
%H= 14/86(100)= 16.18%

C6H12O6= 72+12+96= 180
%C=78/180(100)= 40%
%H=12/180(100)=6.66%
%O=96/180(100)=53.3%

Formula Mínima

C= 85.6% H=14.4%
C= 85.6/12 H=14.4/1
C=7.13 H=14.4
C=7.13/7.13 H=14.4/7.13
C= 1 H=2.01 CH2

C=40% H=6.66% O=53.33%
C= 40/12 H=6.66/1 O=53.33/16
C=3.33/3.33